SOLUTION: If 4^x*n^2 = 4^(x+1)*n and x and n are both positive integers, what is the value of n?

Algebra ->  Expressions-with-variables -> SOLUTION: If 4^x*n^2 = 4^(x+1)*n and x and n are both positive integers, what is the value of n?      Log On


   

Question 1119251: If 4^x*n^2 = 4^(x+1)*n and x and n are both positive integers, what is the value of n?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
If 4%5Ex%2An%5E2+=+4%5E%28x%2B1%29%2An and x and n are both positive integers, what is the value of n?
4%5Ex%2An%5E2+=+4%5E%28x%2B1%29%2An
divide both sides by n
4%5Ex%2An+=+4%5E%28x%2B1%29
n = 4%5E%28x%2B1%29%2F%284%5Ex%29
n = 4%5E%28x%2B1-x%29
n = 4%5E1
n = 4