SOLUTION: 2 sin2 θ + 5 sin θ = −2
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Question 1119207
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2 sin2 θ + 5 sin θ = −2
Answer by
Boreal(15235)
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2 sin^2 x+ 5 sin x+2=0
(2 sin x + 1)(sin x +2)=0
sin x=-1/2, -2. The latter doesn't exist.
sin x =-1/2 at 7/12 pi and 11/12 pi