SOLUTION: What is the solution of the matrix equation? [[2 5][3 7]][[x][y]]=[[2][4]] A) (6, -2) B) (-2, 8) C) (4, 2) D) (-2, 6) Following is a screenshot of the question in c

Algebra ->  Matrices-and-determiminant -> SOLUTION: What is the solution of the matrix equation? [[2 5][3 7]][[x][y]]=[[2][4]] A) (6, -2) B) (-2, 8) C) (4, 2) D) (-2, 6) Following is a screenshot of the question in c      Log On


   



Question 1118972: What is the solution of the matrix equation?
[[2 5][3 7]][[x][y]]=[[2][4]]
A) (6, -2)
B) (-2, 8)
C) (4, 2)
D) (-2, 6)
Following is a screenshot of the question in case of any mistakes or confusion in the way matrices are formatted (this is the only way I currently know to format matrices) https://postimg.cc/image/j4c8ihtnb/

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
What is the solution of the matrix equation?
[[2 5][3 7]][[x][y]]=[[2][4]]
A) (6, -2)
B) (-2, 8)
C) (4, 2)
D) (-2, 6)
Following is a screenshot of the question in case of any mistakes or confusion in the way matrices are formatted (this is the only way I currently know to format matrices) https://postimg.cc/image/j4c8ihtnb/
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To solve this problem, you need piece of paper and a pen (or a pencil).


You also need to know how to multiply a vector with 2 components by 2x2-matrix.


So, in the paper write the matrix and the vector, as you see in the left side from the equality sign "=":


%28matrix%282%2C2%2C+2%2C5%2C+3%2C7%29%29.%28matrix%282%2C1%2C+6%2C-2%29%29 = %28matrix%282%2C1%2C+2%2A6%2B5%2A%28-2%29%2C+3%2A6%2B7%2A%28-2%29%29%29 = %28matrix%282%2C1%2C+2%2C4%29%29.


The most right side/vector is the final result.


The middle vector is an intermediate step. It shows how to multiply the matrix and the vector.


Now compare your very right vector with the given vector.


They coincide, to your fortune.


It means that the vector (6,-2) of the option A) is the solution to given matrix equation.