SOLUTION: #10: Use the appropriate normal distribution to approximate the resulting binomial distribution.
A basketball player has a 80% chance of making a free throw. (Assume that the
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-> SOLUTION: #10: Use the appropriate normal distribution to approximate the resulting binomial distribution.
A basketball player has a 80% chance of making a free throw. (Assume that the
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Question 1118915: #10: Use the appropriate normal distribution to approximate the resulting binomial distribution.
A basketball player has a 80% chance of making a free throw. (Assume that the throws are independent of each other.) What is the probability of her making 95 or more free throws in 120 trials? (Round your answer to four decimal places.) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! mean for 120@80% is np=96
variance is np*(1-p) or 96*.2=19.2
sd is sqrt(var)=4.38
for 95 or more use 94.5
z > (94.5-96)/4.38 or z > -0.34
This probability is 0.6331
