Question 111883: the path of a falling object is given by the fuction s=-16t^2+v0t+s0 where v0 represents the initial velocityin ft/sec and s0 represents the initial height in feet.(the 0's are realy below the v and s ,i couldn't write them below them.)
a. if a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the equation using this information.
b. how high is the rock after 1 second?
c.after how many seconds will the graph reach maximum height?
d. What is the maximum height?
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! a. plug in the given values for v0 and s0
b. using the equation from a., plug in 1 for t and find s
c. the graph of the equation (a) is a downward opening parabola
___ the maximum height is at the vertex, which lies on the axis of symmetry
___ the equation for the axis of symmetry is t=-b/2a
___ (where a is the coefficient of the t^2 term and b is the coefficient of the t term)
d. plug the result from c. into the equation (a) to find s
|
|
|
