Question 1118749: Can you please help me by finding the answer, thank you
If the probability that a bowler will bowl a strike is 0.6, what is the probability that he will get exactly three strikes in six attempts? At least three strikes in six attempts? (Assume that the attempts to bowl a strike are independent of each other. Round your answers to three decimal places.)
exactly three strikes =
at least three strikes =
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
The probability of  successes in  trials where the probability of success on any one trial is the binomial distribution,
\ =\ {{n}\choose{k}}\,\(p\)^k\(1\,-\,p\)^{n-k})
Your is 6 and your  is 0.6.
For the first part, 
For the second part, you need the sum of the probabilities when ,  ,  , and  , which is to say:
\ =\ \sum_{k=3}^6\,{{6}\choose{k}}\,(0.6)^k(0.4)^{6-k})
Get out your calculator, you have a bunch of arithmetic to do.
John
My calculator said it, I believe it, that settles it
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