SOLUTION: (x-4)²+8=0 (x+2)²=3(x+2) (2x-1)²=(x+1)² 2x(x+4)=(x-3)(x-3)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: (x-4)²+8=0 (x+2)²=3(x+2) (2x-1)²=(x+1)² 2x(x+4)=(x-3)(x-3)       Log On


   

Question 1118719: (x-4)²+8=0
(x+2)²=3(x+2)
(2x-1)²=(x+1)²
2x(x+4)=(x-3)(x-3)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
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(x-4)²+8=0
(x+2)²=3(x+2)
(2x-1)²=(x+1)²
2x(x+4)=(x-3)(x-3)
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Those appear to be four separate equations.


%282x-1%29%5E2=%28x%2B1%29%5E2
-
sqrt%28%282x-1%29%5E2%29=sqrt%28%28x%2B1%29%5E2%29
2x-1=0%2B-+%28x%2B1%29
-
EITHER
2x-1=-x-1
3x=0
x=0
OR
2x-1=x%2B1
x-1=1
x=2
-
result: system%28x=0%2COR%2Cx=2%29

Be sure to check if they both work.

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%28x%2B2%29%5E2=3%28x%2B2%29
Simplify the equation first, and then solve. Start THIS WAY:
%28x%2B2%29%5E2-3%28x%2B2%29=0
%28x%2B2%29%28x%2B2-3%29=0, and then continue...
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2x%28x%2B4%29=%28x-3%29%28x-3%29
Simplify first, and then solve...
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