SOLUTION: Solve the following equations for 0c≤ x ≤ 180 a) 3sinθ = 2cosθ b) sinθ - 4cosθ = 0

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Question 1118671: Solve the following equations for 0c≤ x ≤ 180
a) 3sinθ = 2cosθ
b) sinθ - 4cosθ = 0

Found 2 solutions by t0hierry, greenestamps:
Answer by t0hierry(194) About Me  (Show Source):
You can put this solution on YOUR website!
3 sin(theta) = 2 cos(theta)
9sin^2 theta = 4 cos^2 theta
9sin^2 theta = 4(1 - sin^2 theta)
13 sin^2 theta = 4
sin theta = 2/sqrt(13)
sin theta = 4 cos theta
sin^2 theta = 16 cos^2 theta
sin^2 theta = 16 - 16 sin^2 theta
17 sin^2 theta = 16
sin theta = 4/sqrt(17)

Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


3sinx+=+2cosx

%283sinx%29%2F%283cosx%29+=+%282cosx%29%2F%283cosx%29

tanx+=+2%2F3

x = arctan(2/3) = 0.588 radians, to 3 decimal places

sinx-4cosx+=+0

sinx+=+4cosx

sinx%2Fcosx+=+4cosx%2Fcosx

tanx+=+4

x = arctan(4) = 1.3258 radians, to 4 decimal places