SOLUTION: A manufacturer of lighting fixtures has daily production costs of
C = 800 - 30x + 0.75x^2, where C is the total cost (in dollars) and x is the number of units produced.
How m
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Rational-functions
-> SOLUTION: A manufacturer of lighting fixtures has daily production costs of
C = 800 - 30x + 0.75x^2, where C is the total cost (in dollars) and x is the number of units produced.
How m
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Question 1118640: A manufacturer of lighting fixtures has daily production costs of
C = 800 - 30x + 0.75x^2, where C is the total cost (in dollars) and x is the number of units produced.
How many fixtures should be produced each day to yield a minimum cost? Answer by ikleyn(52817) (Show Source):
To solve the problem, you need to find the maximum of the quadratic function
C(x) = .
The maximum of the quadratic function
q(x) =
with positive coefficient "a" is achieved at x = .
In your case b = -30, a = 0.75, therefore the maximum is achieved at
x = = = 40.
Answer. 40 fixture per day provide minimum cost.
