SOLUTION: Copykwik has four photocopy machines: A, B, C, and D. The probability that a given machine will break down on a particular day is given below.
P(A) =
1/48
P(B) =
1/55
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-> SOLUTION: Copykwik has four photocopy machines: A, B, C, and D. The probability that a given machine will break down on a particular day is given below.
P(A) =
1/48
P(B) =
1/55
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Question 1118547: Copykwik has four photocopy machines: A, B, C, and D. The probability that a given machine will break down on a particular day is given below.
P(A) =
1/48
P(B) =
1/55
P(C) =
1/75
P(D) =
1/31
Assuming independence, what is the probability on a particular day that the following will occur?
(a) All four machines will break down (Round your answer to ten decimal places.)
Incorrect: Your answer is incorrect.
(b) None of the machines will break down (Round your answer to three decimal places.) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! All will break down has probability of (1/48)(1/55)(1/75)(1/31)=0.0000001629
none will break down is NOT 1- that bu
(47/48)(54/55)(74/75)(30/31)=0.918
