SOLUTION: L1 is the straight line 2x+3y+6=0. without finding the gradient of L1, find the equation of (a) L2 which passes through the point (1,-2) and parallel to L1 (B) L3 which is perpe

Algebra ->  Finance -> SOLUTION: L1 is the straight line 2x+3y+6=0. without finding the gradient of L1, find the equation of (a) L2 which passes through the point (1,-2) and parallel to L1 (B) L3 which is perpe      Log On


   

Question 1118508: L1 is the straight line 2x+3y+6=0. without finding the gradient of L1, find the equation of
(a) L2 which passes through the point (1,-2) and parallel to L1
(B) L3 which is perpendicular to L1 and passes through the point (2,-1)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel have the same slope or same ratio of coefficients on x and y.

Perpendicular have coefficients such that L1, has Ax+By; and L2, has Bx-Ay.


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L1 is the straight line 2x+3y+6=0. without finding the gradient of L1, find the equation of
(a) L2 which passes through the point (1,-2) and parallel to L1
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2x%2B3y%2B6=0;
2x%2B3y=2%2A1%2B3%2A%28-2%29
2x%2B3y=2-6
highlight%282x%2B3y%2B4=0%29


You do the other question.