SOLUTION: A 200-pound watermelon is 90 percent water. It is dehydrated until it is only 80 percent water. What is its weight after dehydration?

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Question 1118256: A 200-pound watermelon is 90 percent water. It is dehydrated until it is only 80
percent water. What is its weight after dehydration?
Found 2 solutions by josmiceli, josgarithmetic:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There are +.9%2A200+=+180+ pounds of water
+200+-+180+=+20+ pounds is not water
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Then it loses 10% of it's weight, so it loses
+.1%2A200+=+20+ pounds of water
There is +180+-+20+=+160+ pounds of water left
+20+%2B+160+=+180+
Weigh after dehydration is 180 pounds
Feel free to get a 2nd opinon, too

Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
x, amount water removed

The 200 pound melon is 10 percent non-volatile matter; and when dehydrated, brought to 20 percent non-volatile matter.

%28200%2A0.1%29%2F%28200-x%29=0.2
-
20=0.2%28200-x%29

20%2F0.2=200-x

200-x=200%2F2

200-x=highlight%28100%29-------the watermelon's weight after drying to 80%water, 20%non-water.