SOLUTION: Write the equation of a line that is parallel to the straight line y = - 8x + 4 that goes through the point (7, -5)

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Question 1118230: Write the equation of a line that is parallel to the straight line y = - 8x + 4 that goes through the point (7, -5)
Found 2 solutions by Alan3354, greenestamps:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation of a line that is parallel to the straight line y = - 8x + 4 that goes through the point (7, -5)
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Step 1, find the slope of the line, m.
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Parallel lines have the same slope.
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Step 2, use y-y1 = m*(x-x1) where (x1,y1) is the point.

Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


Any line parallel to the line y = -8x+4 will have an equation of the form y = -8x+b.

Find the value of b by plugging in the x and y values of the known point on the line:

y+=+-8x%2Bb
-5+=+-8%287%29%2Bb
-5+=+-56%2Bb
b+=+51

An equation of the line parallel to y = -8x+4 and passing through the point (7,-5) is y = -8x+51.