SOLUTION: At the fair there were half as many men as women. The number of adults was a third that of children. There were 3,600 people at the fair. How many children were there?

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Question 1118225: At the fair there were half as many men as women. The number of adults was a third that of children. There were 3,600 people at the fair. How many children were there?
Found 2 solutions by Fombitz, greenestamps:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
M=W%2F2
So,
W=2M
.
.
W%2BM=C%2F3
C=3W%2B3M%7D%7D%0D%0A.%0D%0A.%0D%0A%7B%7B%7BM%2BW%2BC=3600
Substituting,
M%2B2M%2B3W%2B3M=3600
M%2B2M%2B3%282M%29%2B3M=3600
M%2B2M%2B6M%2B3M=3600
12M=3600
So,
M=3600%2F12
Solve for M then work through and solve for W and C.

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The information about the number of men and women is irrelevant to the question that is asked.

The number of adults is one-third the number of children; it's probably easier for most people to work the problem if we rephrase that to say there are three times as many children as adults.

Then with a total of 3600 people we can mentally find the answer that there were 2700 children and 900 adults.

Or, if you need an algebraic solution....
let x = number of adults
then 3x = number of children
x+3x = 3600
4x = 3600
x = 3600/4 = 900

The number of children is 3x = 3*900 = 2700.