SOLUTION: Brian buses tables at a local cafe. To bus a table, he must clear the dirty dishes and reset the table for the next set of customers. One night he noticed that for every three-fift

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Question 1118220: Brian buses tables at a local cafe. To bus a table, he must clear the dirty dishes and reset the table for the next set of customers. One night he noticed that for every three-fifths of a table that he bused, another table of customers would get up and leave. He also noticed that right after he finished busing a table, a new table of customers would come into the restaurant. However, once every table was empty (no diners were left in the restaurant), nobody else came into the restaurant. Suppose there were six tables with customers and one unbused table. How many new tables of customers would come in before the restaurant was empty? After the last table of customers had left, how many tables were unbused?
Answer by KMST(5328) About Me  (Show Source):
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When 13 sets of customers had left the cafe
( 6 sets who where seating at their tables initially,
and 13-6=7 sets who entered and left the cafe),
Brian has bused 13%283%2F5%29=39%2F5=7%264%2F5 tables,
so highlight%287%29 new tables of customers had come in,
and Brian rushed to lock the door before an 8th set of customers could come in.
At that point the number of unbused tables was
1%2B13-7%264%2F5=highlight%286%261%2F5%29 .

STEPWISE:
As Brian has bused 3%2F5 of a table, 1 table-ful of customers leaves, so now Brian has 1 more table to bus,
to be added to the 2%2F5 left to do of the table he is busing.
For each set of customers that leaves the restaurant,
the number of tables unbused increases by 2%2F5
(compared to the number unbused when the previous set of customers left).
As Brian has bused 5%283%2F5%29=3 tables, 5%2A1=5 table-ful of customers have left,
but at the same time new customers have filled 3 tables.
The number of tables in use has decreased by 5-3=2 as 5 tables emptied.
As Brian has bused 10%283%2F5%29=6 tables, 10%2A1 table-ful of customers have left,
but at the same time new customers have filled 6 tables,
leaving 6-10%2B6=2 tables occupied.
After that, 2%2B1=3 more table-fuls of diners will have to leave for the cafe to be empty,
because by the time the customers in those 2 occupied tables leave,
Brian will have bused 2%283%2F5%29=6%2F5=1%261%2F5 table,
but as he finished busing one table, another table became occupied.
As the last 3 table-fuls of customers left,
a total of 10%2B3=13 table-fuls of customers had left,
Brian had bused 13%283%2F5%29=39%2F5=7%264%2F5 tables,
while the number of tables to be bused had increased by 13 ,
so after Brian locked the door, the number of unbused tables was
1%2B13-7%264%2F5=6%261%2F5 .