SOLUTION: The dimensions of a rectangle are such that its length is 5 in. more than its width. If the length were doubled and if the width were decreased by 2 ​in., the area would be i

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The dimensions of a rectangle are such that its length is 5 in. more than its width. If the length were doubled and if the width were decreased by 2 ​in., the area would be i      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1118210: The dimensions of a rectangle are such that its length is 5 in. more than its width. If the length were doubled and if the width were decreased by 2 ​in., the area would be increased by 162 in.squared. What are the length and width of the​ rectangle?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Length w+5
Width w

The description makes 2%28w%2B5%29%28w-2%29-%28w%2B5%29%2Aw=162.
-
2%28w%5E2%2B3w-10%29-w%5E2-5w=162
2w%5E2%2B6w-20-w%5E2-5w=162
w%5E2%2Bw-182=0
-
w%5E2%2Bw=182
w%28w%2B1%29=182=2%2A7%2A13
highlight_green%28w%28w%2B1%29=13%2A14%29

Width w is 13, so length is w+5=18.


---------------------
width 13
length 18
---------------------