SOLUTION: If the point (6,-2) is on the graph of {{{y=f(x)}}}, what point must be on the graph of the function {{{y=1/(f(-2x)+3)}}}?

Algebra ->  Rational-functions -> SOLUTION: If the point (6,-2) is on the graph of {{{y=f(x)}}}, what point must be on the graph of the function {{{y=1/(f(-2x)+3)}}}?      Log On


   

Question 1118124: If the point (6,-2) is on the graph of y=f%28x%29, what point must be on the graph of the function y=1%2F%28f%28-2x%29%2B3%29?
Answer by ikleyn(52784) About Me  (Show Source):
You can put this solution on YOUR website!
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Answer.  The point  (-3,1).


Substitute x= -3 into y(x) to get y(-3) = 1%2F%28f%28%28-2%29%2A%28-3%29%29+%2B3%29 = 1%2F%28f%286%29%2B3%29 = 1%2F%28-2%2B3%29 = 1%2F1 = 1.


It is why the point (-3,1) lies on the graf of the function  y(x) = 1%2F%28f%28-2x%29%2B3%29.