SOLUTION: There were 390 people at a play. Admission was $12 each for adults and $5.50 for children. The receipts were $3991. How many adults and how many children attended?

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Question 1117899: There were 390 people at a play. Admission was $12 each for adults and $5.50 for children. The receipts were $3991. How many adults and how many children attended?
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Similar problem, different numbers.
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Sally has 52 coins all dimes and nickels that have the total value of $4.20. How many nickels does this bitch have?
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n + d = 52
5n +10d = 420
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Or:
52 nickels = 260
Each nickel replaced by a dime adds 5 cents.
420 - 260 = 160
160/5 = 32 replacements by dimes.

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
a, adults
c, children
system%28a%2Bc=390%2C12a%2B5.5c=3991%29

Solve the system anyway you want.

--

a=390-c
-
12%28390-c%29%2B5.5c=3991
4680-12c%2B5.5c=3991
-6.5c%2B4680=3991
-6.5c=3991-4680
6.5c=4680-3991
c=%284680-3991%29%2F6.5
-
c=106------children
a=284------adults