SOLUTION: Solve for all solutions between 0 and 360 degrees. Round the solution to the nearest tenth of a degree. {{{tan^2(x)= 1+sec(x)}}} Thank you!

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Question 1117815: Solve for all solutions between 0 and 360 degrees. Round the solution to the nearest tenth of a degree.

tan%5E2%28x%29=+1%2Bsec%28x%29


Thank you!
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
















Let













Hence





Now all you need is the two angles in the desired interval that have a cosine value of negative one-half. Then you have to decide whether the stated interval is inclusive of the low end, the high end, both, or neither.

In other words, does the phrase "between 0 and 360 degrees" mean







or



Because in the first case:

Does not exist

In the second case:



In the third case:



And in the fourth case:

or

John

My calculator said it, I believe it, that settles it