SOLUTION: Solve the system by back substitution: 4x+8y+2z+6w= -5 -y-6z-2w= -8 -3z-3w= -6 -5w= -15 The set solution is: _,_,_,_

Algebra ->  Finance -> SOLUTION: Solve the system by back substitution: 4x+8y+2z+6w= -5 -y-6z-2w= -8 -3z-3w= -6 -5w= -15 The set solution is: _,_,_,_      Log On


   

Question 1117726: Solve the system by back substitution:
4x+8y+2z+6w= -5
-y-6z-2w= -8
-3z-3w= -6
-5w= -15
The set solution is: _,_,_,_
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


1. Solve the last equation for .

2. Substitute the value of you discovered in step 1 into the third equation and then solve for .

3. Substitute the value of from step 1 and the value of from step 2 into the second equation and then solve for .

4. Substitute the values of , , and from the first three steps into the first equation and solve for
The way you are asking for the answer is incorrect. A list of the values of the four variables is NOT the solution set of the 4X4 system of equations. The solution set of this system has a single element, namely the ordered quadruple of the form . The solution set would then need to be written: .

John

My calculator said it, I believe it, that settles it