Question 1117672: Five balls are randomly drawn without replacement from a bag containing 4 red balls and 6 black balls. What is the probability that at least 3 red balls will be drawn?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! This would be 3 or 4 red balls.
Total number of ways is 10C5 or 252
For 3, it is 4C3 red and 6C2 for the other, black. This is 4*15 or 60 ways.
For 4, it is 4C4 and 6C1, and this is 1*6 or 6 ways.
There are 66 ways, so the probability is 66/252 or 0.262.
|
|
|
