SOLUTION: Amy, Chau, and Juan have a total of 90 in their wallets. Amy has 5 more than Chau. Juan has 3 times what Amy has. How much do they have in their wallets?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Amy, Chau, and Juan have a total of 90 in their wallets. Amy has 5 more than Chau. Juan has 3 times what Amy has. How much do they have in their wallets?       Log On


   

Question 1117671: Amy, Chau, and Juan have a total of 90
in their wallets. Amy has 5
more than Chau. Juan has 3
times what Amy has. How much do they have in their wallets?





Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
Amy   + Chau + Juan = 90


A     + C    + J    = 90

||             ||

(C+5) + C + 3*(C+5) = 90


3C + 5 + 15  = 90


5C + 20 = 90  ====>  5C = 90 - 20 = 70  ====>  C = 70%2F5 = 14.


Answer.  Chau has  14;   Amy  has 14+5 = 19;  Juan has  3*19 = 57.


Check    14 + 19 + 57 = 90.   ! Correct !

Solved.


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Amy, Chau, and Juan have a total of 90:
Amy%2B+Chau%2BJuan=90....eq.1

if Amy has 5 more than Chau, we have
Amy=Chau%2B5=>Chau=Amy-5...eq.2
if Juan has 3 times what Amy has, we have
Juan=+3%2AAmy...eq.3

Amy%2B+Chau%2BJuan=90....eq.1 substitute values rom eq.2 and eq.3
Amy%2B+Amy-5%2B3%2AAmy=90
5%2AAmy=90%2B5
Amy=95%2F5
Amy=+19
Chau=Amy-5=>Chau=19-5=>Chau=14
Juan=+3%2AAmy=>Juan=+3%2A19=>Juan=+57

How much do they have in their wallets?
Amy has 19
Chau has 14
Juan has 57