You can put this solution on YOUR website! given that sin a =-4/5 and tan a >0, find all the trigonometric ratios of a
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sin < 0 & tan > 0 --> Q3
sin = y/r = -4/5 (given)
x = sqrt(r^2 - y^2) = -3
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cos = y/r = -3/5
tan = y/x = -4/-3 = 4/3
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cot = 1/tan
sec = 1/cos
csc = 1/sin