SOLUTION: A hand of 5 cards is dealt from a standard deck How many hands with 2 king and 3 clubs are possible?

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Question 1117621: A hand of 5 cards is dealt from a standard deck
How many hands with 2 king and 3 clubs are possible?

Found 2 solutions by josmiceli, greenestamps:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Order is not important, so this is a problem
using combinations, not permutations
Number of hands = C( 3,2 ) * C( 12,3 )
C( 3,2 ) = +3%21+%2F+%28%28+3+-+2++%29%21+%2A+2%21+%29+
C( 3,2 ) = +6+%2F+2+
C( 3,2 ) = +3+
and
C( 12,3 ) = +12%21+%2F+%28%28+12+-+3+%29%21+%2A+3%21+%29+
C( 12,3 ) =
C( 12,3 ) = +%28+12%2A11%2A10+%29+%2F+%28+3%2A2%2A1+%29+
C( 12,3 ) = +1320+%2F+6+
C( 12,3 ) = +220+
------------------------
C( 4,2 )*C( 13,3 ) = +3%2A220+
+3%2A22+=+660+
There are 660 possible hands
Note that one of the kings counted is a club, so that
won't work, and one of the clubs being counted is a king
and that won't work either, so I need to account for them
Feel free to get another opinion on this

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The king of clubs can not be one of the cards. If it were, then "2 kings and 3 clubs" would be only 4 cards; but the problem says 5 cards were dealt.

So the hands we are considering are those that contain 2 of the 3 kings that are not clubs and 3 of the 12 clubs that are not kings.

So the answer from the other tutor is correct:

C%283%2C2%29%2AC%2812%2C3%29+=+3%2A220+=+660