SOLUTION: please help me sketch the graph for {{{-x^2+ 2x +3}}} and what is the range ,please show all working.

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Question 1117498: please help me sketch the graph for -x%5E2%2B+2x+%2B3 and what is the range ,please show all working.
Found 2 solutions by rothauserc, greenestamps:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = -x^2 +2x +3
:
this is a parabola that curves downward
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the x coordinate for the vertex is -b/2a = -2/2(-1) = 1
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f(1) is the y coordinate(highest point of the parabola) = -(1^2) +2(1) +3 = 4
:
+graph%28+300%2C+200%2C+-11%2C+13%2C+-140%2C+10%2C+-x%5E2+%2B2x+%2B3%29+
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range of f(x) over the real numbers is f(x) < or = 4
:

Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


The solution by the other tutor, using x = -b/2a for the x coordinate of the vertex, is one good way to work a problem like this.

Another useful method to know is to put the equation in standard form:

y-k+=+a%28x-h%29%5E2

or

y+=+a%28x-h%29%5E2%2Bk

In either of these forms, the vertex is at (h,k).

For your example....

y+=+-x%5E2%2B+2x+%2B3

factor out the leading coefficient

y+=+-1%28x%5E2-2x%29%2B3

complete the square

y+=+-1%28x%5E2-2x%2B1%29%2B3%2B1

y+=+-1%28x-1%29%5E2%2B4 or y-4+=+-1%28x-1%29%5E2

These forms tell you that the vertex is at (1,4); the a=-1 tells you that the parabola opens downward. That makes the maximum value of the function is 4; so the range is y <= 4.