SOLUTION: Find the 3 cube roots of -i in POLAR FORM: rcis(theta)

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Question 1117278: Find the 3 cube roots of -i in POLAR FORM: rcis(theta)
Answer by math_helper(2461) About Me  (Show Source):
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First find r and +theta+. The value of r is 1 by inspection, +theta+=+-pi%2F2+ also by inspection.

and the cube root of this is :
; k=0, 1, 2


So the 3 cube roots of -i are (in polar form):
for k=0, 1, 2