SOLUTION: : If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: : If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.       Log On


   

Question 1117160: : If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.
Found 2 solutions by KMST, Alan3354:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Your formula for height has a typo.
The height %28h%29 (in feet) after t seconds can be calculated as
h=-16%2At%5E2%2B123%2At .
We can find the height after t=5 seconds,
by just plugging in 5 for t in the correct formula:
h=-16%2A5%5E2%2B123%2A5=-16%2A25%2B615=-400%2B615=215 .
Five seconds after the object is launched upwards,
its height is highlight%28215+feet%29 .

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
: If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.
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Sub 5 for t.