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1. Solve using logical analysis
In accordance with the condition, you can group all the coins in the sets, containing (one 25-centavo and five 10-centavo coins) each.
Each the set is worth (25+5*10) = 75 centavo.
Hence, the number of sets is 
= 20.
It gives the
Answer. 20 of 25-centavo and 100 of 10-centavo.
Solved.
2. Algebra solution
There are x 25-centavo and 5x 10-centavo coins.
The money ("the value") equation is
25x + 10*(5x) = 1500 centavo, or
75x = 1500 ====> x = = 20,
which gives you the same answer.
Solved.
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On coin problems, see the lessons
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- Three methods for solving standard (typical) coin word problems
- More complicated coin problems
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
- OVERVIEW of lessons on coin word problems
in this site.
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
