SOLUTION: Find a value of x such that: (3+4)(3²+4²)(3^4+4^4)(3^8+4^8)(3^16+4^16)(3^16+4^16)(3^32+4^32)=4^x-3^x

Algebra ->  Exponents -> SOLUTION: Find a value of x such that: (3+4)(3²+4²)(3^4+4^4)(3^8+4^8)(3^16+4^16)(3^16+4^16)(3^32+4^32)=4^x-3^x      Log On


   

Question 1117072: Find a value of x such that:
(3+4)(3²+4²)(3^4+4^4)(3^8+4^8)(3^16+4^16)(3^16+4^16)(3^32+4^32)=4^x-3^x
Answer by ikleyn(52858) About Me  (Show Source):
You can put this solution on YOUR website!
.
If you multiply the left side by  (3-4),  // which is (-1), // you will get that the left side is


4%5E64-3%5E64.


If you then compare it with the right side, you will find that  x = 64.

Solved.