SOLUTION: I am not sure of how to set up this equation and solve it: Write an equation for a parabola with a focus of (2,2) and directrix of y =4 Options: y = 1/4 (x-2) ^2 +3 y =

Algebra ->  Length-and-distance -> SOLUTION: I am not sure of how to set up this equation and solve it: Write an equation for a parabola with a focus of (2,2) and directrix of y =4 Options: y = 1/4 (x-2) ^2 +3 y =       Log On


   

Question 1117018: I am not sure of how to set up this equation and solve it:
Write an equation for a parabola with a focus of (2,2) and directrix of y =4
Options:
y = 1/4 (x-2) ^2 +3
y = - 1/4 (x-2) ^2 + 3
y = -1/2 (x+2)^2 +3
y =1/2 (x+2)^2 +3
Answer by josgarithmetic(39626) About Me  (Show Source):
You can put this solution on YOUR website!
You could use the Distance Formula definition for Parabola and start with this:

Points (x,y) will fit
sqrt%28%28x-2%29%5E2%2B%28y-2%29%5E2%29=sqrt%28%28x-x%29%5E2%2B%28y-4%29%5E2%29

Work through the algebra steps to put into the form you want and then make the proper choice.