SOLUTION: A tourist can bicycle 32 Miles in the same time as he can walk 6 miles. If he can ride 13 mph faster than he can walk, how much time should he allow to walk a 25-mile trail?
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: A tourist can bicycle 32 Miles in the same time as he can walk 6 miles. If he can ride 13 mph faster than he can walk, how much time should he allow to walk a 25-mile trail?
Log On
Question 1116954: A tourist can bicycle 32 Miles in the same time as he can walk 6 miles. If he can ride 13 mph faster than he can walk, how much time should he allow to walk a 25-mile trail? Answer by ikleyn(52756) (Show Source):
Let w be his (or her) walking speed, in miles per hour.
Then you have this equation from the condition
= ,
which has the solution w = 3 miles per hour.
(You can easily solve the equation on your own - I solved it mentally).
Then the time to walk 25 miles is = hours = 8 hours and 20 minutes.