SOLUTION: A tourist can bicycle 32 Miles in the same time as he can walk 6 miles. If he can ride 13 mph faster than he can walk, how much time should he allow to walk a 25-mile trail?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A tourist can bicycle 32 Miles in the same time as he can walk 6 miles. If he can ride 13 mph faster than he can walk, how much time should he allow to walk a 25-mile trail?      Log On


   



Question 1116954: A tourist can bicycle 32 Miles in the same time as he can walk 6 miles. If he can ride 13 mph faster than he can walk, how much time should he allow to walk a 25-mile trail?
Answer by ikleyn(52756) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let w be his (or her) walking speed, in miles per hour.


Then you have this equation from the condition


32%2F%28w%2B13%29 = 6%2Fw,


which has the solution  w = 3  miles per hour.   

(You can easily solve the equation on your own - I solved it mentally).


Then the time to walk 25 miles is  25%2F3 = 81%2F3 hours = 8 hours and 20 minutes.

Solved.