SOLUTION: Find 3 consecutive odd integers such that the sum of the first and second is 27 less than 3 times the third

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Question 1116942: Find 3 consecutive odd integers such that the sum of the first and second is 27 less than 3 times the third
Found 2 solutions by Boreal, rothauserc:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
integers are x, x+2 and x+4
(x+x+2)+27=3(x+4)
(2x+2)+27=3x+12
2x+29=3x+12
-x=-17
x=17
The integers are 17,19,21 ANSWER
36 is 27 less than 63

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
let x, x+2, x+4 be three consecutive odd integers, then
:
x +x+2 +27 = 3 * (x+4)
:
2x +29 = 3x +12
:
x = 17
:
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the three consecutive odd integers are 17, 19, 21
:
check answer
:
17+19 = 36 and 3*21 = 63
:
63 - 36 = 27
:
the answer checks
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