SOLUTION: Express as an equivalent logarithm: log (x + 2) + log 1 – 3 log y

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Question 1116505: Express as an equivalent logarithm: log (x + 2) + log 1 – 3 log y
Answer by Alan3354(69443) About Me  (Show Source):
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Express as an equivalent logarithm: log (x + 2) + log 1 – 3 log y
log(1) = 0
log (x + 2) – 3 log y = log%28%28x%2B2%29%2Fy%5E3%29