SOLUTION: A store is having a sale on chocolate chips and walnuts. For 5 pounds of chocolate chips and 3 pounds of walnuts, the total cost is $23. For 2 pounds of chocolate chips and 12 poun

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A store is having a sale on chocolate chips and walnuts. For 5 pounds of chocolate chips and 3 pounds of walnuts, the total cost is $23. For 2 pounds of chocolate chips and 12 poun      Log On


   



Question 1116362: A store is having a sale on chocolate chips and walnuts. For 5 pounds of chocolate chips and 3 pounds of walnuts, the total cost is $23. For 2 pounds of chocolate chips and 12 pounds of walnuts, the total cost is
$47.Find the cost for each pound of chocolate chips and each pound of walnuts.

Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
.
A two-equations setup

5c +  3w = 23    (1)
2c + 12w = 47    (2)


Solve by Elimination. For it, multiply eq(1) by 4 (both sides). Keep eq(2) as is:


20c + 12w = 92   (1')
 2c + 12w = 47   (2')


Subtract eq(2') from  eq(1'). The terms "12w" will cancel each other, leaving you single equation for only one unknown "c".

It is how the Elimination method works.


20c - 2c = 92 - 47 = 45  ====>  c = 45%2F18 = 2.50.


Now from eq(2)  2*2.50 + 12w = 47  ====>  12w = 47 - 2*2.50 = 42  ====>  w = 42%2F12 = 3.50.


Answer.  cost for each pound of chocolate chips is $2.50  and of each pound of walnuts $3.50. 

Solved.

On the way,  you learned on how the Elimination method works.

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The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".


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Free of charge online textbook in ALGEBRA-I
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