SOLUTION: A palindrome number is a number that is the same when it’s digits are reversed. Find the largest palindrome number that is the product of two 2-digit numbers?

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Question 1116259: A palindrome number is a number that is the same when it’s digits are reversed. Find the largest palindrome number that is the product of two 2-digit numbers?
Answer by KMST(5328) About Me  (Show Source):
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99%2A99=9801 , so a product of two two-digit numbers is at most 9801 ,
and a palindrome that is a product of two two-digit numbers is less than 9801 .
The largest palindrome that is less than 9801 is 9779 .

If the first two digits are a and b in that order,
the number's digit read like abba ,
and the number is a multiple of 11 ,
because its value is
1000a%2B100b%2B10b%2Ba=1001a%2B110b=11%2A91a%2B11%2A10b=11%2891a%2B10b%29 .
If that %2891a%2Bb%29 factor can be further factored as
a two-digit number t times a single digit number d ,
the palindrome can be factored as the product of the two-digit numbers 11d and t :
11%2891a%2B10b%29=11%2Ad%2At=%2811d%29%2At
For example, 9779 , with system%28a=9%2Cb=7%29 can be factored as
9779=11%2891%2A9%2B10%2A7%29=11%28819%2B70%29=11%2A889=11%2A7%2A127=77%2A127 ,
and does not work.

If we try all possible b values for a=9 , we find
.
Out of all those values for 91a%2Bb ,
none is divisible by 2 , or 5 , or 7 ,
and only two of them are divisible by 3 .
That rules out all possible digit factors except 3 and 9%7D%7D+.%0D%0AOnly+one+of+those+values%2C+%7B%7B%7B819=9%2A91 , is divisible by 9 .
So, with system%28a=9%2Cb=0%2C91a%2B10b=91%2A9=819%29 ,
highlight%289009%29=11%2A819=11%2A9%2A91=99%2A91
is a palindrome that can be written as a product of two two-digit numbers.
There will be others, such as 8118=11%2A738=11%2A9%2A82=99%2A82 ,
but highlight%289009%29 is the largest palindrome number that is the product of two 2-digit numbers.