.
I don't know about the cost of producing the box, and I think that this passage is not relevant to the rest of the condition.
But I know which dimensions will minimize the surface area of the box (which directly relate to the cost of the material).
The dimensions what minimize the surface area are 15 x 15 x 15 centimeters:  the box must be a cube.
It is easy to get this result analytically, using Calculus.
The surface area of the (x,y,z)-box is  A(x,y,z) = 2*(xy + xz + yz).
The volume = xyz = 3375,  so  z =  .
Therefore, A(x,y,z) =
.
Therefore, A(x,y,z) =  at the given volume.
The conditions
  at the given volume.
The conditions   =
 =  = 0 give
 = 0 give
     -
 -  = 0  ====>  x^3 = 3375  ====>  x =
 = 0  ====>  x^3 = 3375  ====>  x =  = 15,   and
 = 15,   and
     -
 -  = 0  ====>  y^3 = 3375  ====>  y =
 = 0  ====>  y^3 = 3375  ====>  y =  = 15.
And then  z =
 = 15.
And then  z =  =
 =  = 15.
 = 15.
Solved.