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a) Answer. 9000 four digit numbers.
It is the full number of existing 4-digit numbers,
and it is how many four digits number can be formed with the 10 digits 0-9, if repetitions are allowed.
b) Answer. 9*9*8*7 = 4536.
Very first (the left-most) digit can be any of 9 digits from 1 to 9
(zero is excluded in this position);
Next digit can be any of 9 remaining digits (zero is included in this position)
Next digit can be any of 8 remaining digits;
Next (and the last) digit can be any of 7 remaining digits.
In all, there are 9*9*8*7 opportunities.
b) Answer. 9*8*7 = 504.
The digit zero is fixed in the "ones" position.
Very first (the left-most) digit can be any of 9 digits from 1 to 9
(zero is excluded in this position);
Next digit can be any of 8 remaining digits;
Next digit can be any of 7 remaining digits.
In all, there are 9*8*7 opportunities.
Solved.