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Question 1116093: Katie invested a total of $4000, part at 4% simple interest and part at 5% simple interest. At the end of 1 year, the investments had earned $174 interest. How much was invested at each rate?
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Katie invested a total of $4000, part at 4% simple interest and part at 5% simple interest.
At the end of 1 year, the investments had earned $174 interest.
How much was invested at each rate?
:
let x = amt invested at at 5%
the total invested, is $4000, therefore:
(4000-x) = amt invested at 4%
:
.04(4000-x) + .05x = 174
distribute the .04
160 - .04x + .05x = 174
.01x = 174 - 160
.01x = 14
x = 14/.01
x = $1400 invested at 5%
then
4000-1400 = $2600 invested at 4%
:
:
Check this, find actual amt earned from each
.05*1400 = $70
.04*2600 = $104
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total earned: $174
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! Katie invested a total of $4000, part at 4% simple interest and part at 5% simple interest. At the end of 1 year, the investments had earned $174 interest. How much was invested at each rate?
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Quantity:: r + v = 4000
Interest:: 0.04r + 0.05v = 174
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Modify for elimination::
4r + 4v = 16000
4r + 5v = 17400
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Subtract and solve for "v"::
v = $1400 (amt. invested at 5%)
r = $3600 (amt. invested at 4%)
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Cheers,
Stan H.
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