SOLUTION: Find the area of the triangle using law of sines/cosines, given the following: A = 56.80 degrees b = 32.67 meters c = 52.89 meters

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Question 1116074: Find the area of the triangle using law of sines/cosines, given the following:
A = 56.80 degrees
b = 32.67 meters
c = 52.89 meters
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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Area of a triangle (of any triangle) is half the product its two side lengths by the sine of the concluded angle:


Area = %281%2F2%29%2Ab%2Ac%2Asin%28A%29 = %281%2F2%29%2A32.67%2A52.89%2Asin%2856.80%5Eo%29.