SOLUTION: In a nationwide telephone poll of 1500 U.S. adults conducted for the freedom Forum by the Center for Survey Research and Analysis at the University of Connecticut, 43% people of th

Algebra ->  Probability-and-statistics -> SOLUTION: In a nationwide telephone poll of 1500 U.S. adults conducted for the freedom Forum by the Center for Survey Research and Analysis at the University of Connecticut, 43% people of th      Log On


   

Question 1116063: In a nationwide telephone poll of 1500 U.S. adults conducted for the freedom Forum by the Center for Survey Research and Analysis at the University of Connecticut, 43% people of those polled said that they think that balancing the budget is more important than cutting taxes in the United States? Suppose we want to estimate such a proportion in the population?
i) Identify (describe as much as possible) the parameter? Is it known?
ii) Find a 90% confidence interval for all the adults who hold this opinion? Suppose the researcher has already computed the 90% margin of error as 0.029?
Your a 90% Confidence interval for the true pop: proportion?
Answer by bobbiensam(1) About Me  (Show Source):
You can put this solution on YOUR website!
A number increased by 2/3 of the number is 35. What is the number?
Let n = "the number"
n + 2%2F3n = 35
12%2F3n = 35
which is

5% = 35
multiply both sides by 3, gets rid of the fraction
5n = 3(35)
5n = 105
divide both sides by 5
n = 105%2F5
n = 21 is the number
:
You can check this in the original equation