SOLUTION: The length of a rectangle is 5 ft
more than double the width, and the area of the rectangle is 42 ft^2
. Find the dimensions of the rectangle.
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-> SOLUTION: The length of a rectangle is 5 ft
more than double the width, and the area of the rectangle is 42 ft^2
. Find the dimensions of the rectangle.
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Question 1116041: The length of a rectangle is 5 ft
more than double the width, and the area of the rectangle is 42 ft^2
. Find the dimensions of the rectangle. Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! let l be the length of the rectangle and w be its width
:
l = 2w +5
:
l * w = area of rectangle
:
(2w+5) * w = 42
:
2w^2 +5w = 42
:
subtract 42 from both side of the =
:
2w^2 +5w -42 = 0
:
(2w-7) * (w+6) = 0
:
there are two solutions for w
:
w = 7/2 = 3.5 and w = -6
:
we reject the negative value for w
:
l = 2(3.5) +5 = 12
:
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l = 12 feet and w = 3.5 feet
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