SOLUTION: how many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze?
Question 1115906: how many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze? Answer by ikleyn(52790) (Show Source):
let x = the amount of the 65% antifreeze to mix (in gallons).
Then your basic equation is
0.65x + 0.2(50-x) = 0.56*50. <<<---=== it is the balance equation for the pure antifreeze.
Simplify it and solve for x.
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It is a standard and typical mixture word problem.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
In this list, I specially marked by (*) the lesson related to antifreeze.
