SOLUTION: In 1996, an outbreak of a disease infected 18people in a large community. By 1997, the number of those infected had grown to 38. Find an exponential growth function that fits th
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-> SOLUTION: In 1996, an outbreak of a disease infected 18people in a large community. By 1997, the number of those infected had grown to 38. Find an exponential growth function that fits th
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Question 1115870: In 1996, an outbreak of a disease infected 18people in a large community. By 1997, the number of those infected had grown to 38. Find an exponential growth function that fits the data. (Round decimals to three places.)
You can put this solution on YOUR website! The initial population is 18 and 1 year(t=1) later it is 38
:
38 = 18 * e^(1*k), where k is the growth rate
:
e^(1*k) = 38/18
:
take the natural log(ln) of both sides of the =
:
k = ln(38/18) = 0.747
:
P(t) = 18 * e^(0.747*t), where P(t) is the population affected at time t(years since 1996)
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