SOLUTION: the sum of two numbers is 38. The second is 5 more than 2 times the first. What are the two numbers?

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Question 111577: the sum of two numbers is 38. The second is 5 more than 2 times the first. What are the two numbers?
Answer by wgunther(43) About Me  (Show Source):
You can put this solution on YOUR website!
Let them be a and b. a+b=38. b-5=2a. Solve.
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Ca+%2B+1%5Cb+=+38%2C%0D%0A++++-2%5Ca+%2B+1%5Cb+=+5+%29%0D%0A++We'll use substitution. After moving 1*b to the right, we get:
1%2Aa+=+38+-+1%2Ab, or a+=+38%2F1+-+1%2Ab%2F1. Substitute that
into another equation:
-2%2A%2838%2F1+-+1%2Ab%2F1%29+%2B+1%5Cb+=+5 and simplify: So, we know that b=27. Since a+=+38%2F1+-+1%2Ab%2F1, a=11.

Answer: system%28+a=11%2C+b=27+%29.