SOLUTION: Find the value of c so that the equation will have exactly one rational solution. p^2-10p+c=0

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Question 1115736:
Find the value of c so that the equation will have exactly one rational solution.
p^2-10p+c=0

Found 2 solutions by josgarithmetic, jim_thompson5910:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Discriminant would be 0.

%28-10%29%5E2-4%2A1%2Ac=0
Solve this.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First I'm going to alter p%5E2-10p%2Bc=0 so that it's in a more familiar form
p^2-10p+c=0
x^2-10x+c=0 ... replace every 'p' with 'x'
1x^2-10x+c=0 ... rewrite x^2 as 1x^2
1x^2+(-10)x+c=0 ... rewrite the "1x^2-10x" as "1x^2+(-10)x"

Note how 1x%5E2%2B%28-10%29x%2Bc=0 is in the form ax%5E2%2Bbx%2Bc=0

It might be better to line up the terms like so
1x^2+(-10)x+c=0
ax^2+bx+c=0

Which helps us see that
a = 1
b = -10
c = unknown for now

Now turn to the discriminant formula
d+=+b%5E2+-+4ac
Exactly one rational solution occurs when d+=+0

So we'll plug in a = 1, b = -10, and d = 0. Then we'll solve for c
d+=+b%5E2+-+4ac

0+=+%28-10%29%5E2+-+4%281%29c

0+=+100-4c

4c+=+100

c+=+100%2F4

c+=+25 (this is the final answer)

So the equation p%5E2-10p%2Bc=0 becomes p%5E2-10p%2B25=0

I'll leave it as an exercise for you to confirm that p%5E2-10p%2B25=0 has exactly one solution, and to find the solution. Though this is optional, its good to practice. Hint: Quadratic Formula