SOLUTION: Please help Given that the right triangle ABC as shown, fill in the values of tan θ and sec θ, and prove in general that 1 + tan^2 θ = sec^2 θ Tan θ =__

Algebra ->  Trigonometry-basics -> SOLUTION: Please help Given that the right triangle ABC as shown, fill in the values of tan θ and sec θ, and prove in general that 1 + tan^2 θ = sec^2 θ Tan θ =__      Log On


   

Question 1115710: Please help
Given that the right triangle ABC as shown, fill in the values of tan θ and sec θ, and prove in general that 1 + tan^2 θ = sec^2 θ
Tan θ =_____
Sec θ=_____
Here is a picture of the problem
https://ibb.co/mzmHuH
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The tangent is a/b
The secant is the reciprocal of the cosine and is c/b
1+(a^2/b^2)=(b^2+a^2)/b^2=c^2/b^2, because a^2+b^2=c^2
c/b is the secant, so (c/b)^2 theta is sec^2, theta