SOLUTION: A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in successi
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-> SOLUTION: A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in successi
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Question 1115708: A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in succession, without replacement.
What is the probability that the first two candies drawn are orange and the third is brown? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! There are 57 total
probability of first two orange is (3/57)(2/56)
and third brown is 13/55
Multiplying all of them and the probability is 0.0004
