SOLUTION: The notation n! = n•(n-1)•(n–2)• • • • • •3•2•1. For example, 5! = 5•4•3•2•1 = 120. How many zeroes occur at the end of the expanded numeral for 100!?
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-> SOLUTION: The notation n! = n•(n-1)•(n–2)• • • • • •3•2•1. For example, 5! = 5•4•3•2•1 = 120. How many zeroes occur at the end of the expanded numeral for 100!?
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Question 1115588: The notation n! = n•(n-1)•(n–2)• • • • • •3•2•1. For example, 5! = 5•4•3•2•1 = 120. How many zeroes occur at the end of the expanded numeral for 100!? Answer by MathLover1(20850) (Show Source):
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The number of trailing zeros in the decimal representation of , the factorial of a non-negative integer , can be determined with this formula:
+...+ where must be chosen such that
