SOLUTION: The following table shows U.S. employment figures for 2014, broken down by educational attainment. All numbers are in millions, and represent civilians aged 25 years and over. Thos

Algebra ->  Probability-and-statistics -> SOLUTION: The following table shows U.S. employment figures for 2014, broken down by educational attainment. All numbers are in millions, and represent civilians aged 25 years and over. Thos      Log On


   



Question 1115438: The following table shows U.S. employment figures for 2014, broken down by educational attainment. All numbers are in millions, and represent civilians aged 25 years and over. Those classed as "not in labor force" were not employed nor actively seeking employment.
Employed Unemployed Not in Labor Force Total
Less Than High
School Diploma 9.9 1.0 13.2 24.1
High School
Diploma Only 33.9 2.2 25.9 62.0
Some College or
Associate's Degree 35.3 2.0 18.4 55.7
Bachelor's Degree
or Higher 48.8 1.6 16.9 67.3
Total 127.9 6.8 74.4 209.1
Find the probability that a person was employed, given that the person had some college or an associate's degree. Round your answer to two decimal places.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The table is a bit messy, so I cleaned it up. It should look like this (let me know if otherwise)



The key phrase is "given that the person had some college or an associate's degree". So that means that whoever we randomly pick, we know 100% that this person had some college or an associate's degree. Because of this 100% certainty, we must ignore the other data values. Only focus on the "some college or an associate's degree" row. I'll highlight it in yellow



From that highlighted row, there are 35.3 million people employed (see column 1 of that row) out of 55.7 million people total (see last column of that highlighted row).

Now we divide those two values to get %2835.3%29%2F%2855.7%29+=+0.63375 which is approximate to 5 decimal places.

Rounding this to two decimal places gives the final answer of 0.63