You can put this solution on YOUR website! x^2-7x+10<0
(x-2)(x-5)<0
Now for the above equation to be true x-2 and x-5 should
be of opposite signs simultaneously.
Now when x<2, then both factors are negative therefore the whole equation is positive.
Therefore it is not a part of the solution.
When 5>x>2 (x-2)>0 and (x-5)<0
therefore the above equation is negative 5
When x>5 both
the factors are
positive
therefore it is
not a part of the solution.
Hence the solution is
5
x=(2,5).